Revert "可以处理生成加法的IR"
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@@ -1,5 +0,0 @@
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int main() {
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int a = 1;
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int b = 2;
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return a + b;
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}
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@@ -1,5 +0,0 @@
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int main() {
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int a = 1;
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int b = 2;
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return a + b;
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}
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