Replace Fortran bssn_rhs with C implementation and add C helper kernels

- Modify bssn_rhs_c.C to use existing project headers (macrodef.h, bssn_rhs.h)
- Update makefile: remove bssn_rhs.o from F90FILES, add CFILES with OpenMP
- Keep Fortran helper files (diff_new.f90, kodiss.f90, lopsidediff.f90) for other Fortran callers

[copilot: fix compiling errors & a nan error]

Co-authored-by: ianchb <i@4t.pw>
Co-authored-by: copilot-swe-agent[bot] <198982749+copilot@users.noreply.github.com>
This commit is contained in:
wingrew
2026-02-25 18:59:33 +08:00
committed by ianchb
parent d942122043
commit 8a9c775705
9 changed files with 2224 additions and 8 deletions

View File

@@ -0,0 +1,255 @@
#include "tool.h"
/*
* 你需要提供 symmetry_bd 的 C 版本(或 Fortran 绑到 C 的接口)。
* Fortran: call symmetry_bd(3,ex,f,fh,SoA)
*
* 约定:
* nghost = 3
* ex[3] = {ex1,ex2,ex3}
* f = 原始网格 (ex1*ex2*ex3)
* fh = 扩展网格 ((ex1+3)*(ex2+3)*(ex3+3)),对应 Fortran 的 (-2:ex1, ...)
* SoA[3] = 输入参数
*/
void lopsided(const int ex[3],
const double *X, const double *Y, const double *Z,
const double *f, double *f_rhs,
const double *Sfx, const double *Sfy, const double *Sfz,
int Symmetry, const double SoA[3])
{
const double ZEO = 0.0, ONE = 1.0, F3 = 3.0;
const double TWO = 2.0, F6 = 6.0, F18 = 18.0;
const double F12 = 12.0, F10 = 10.0, EIT = 8.0;
const int NO_SYMM = 0, EQ_SYMM = 1, OCTANT = 2;
(void)OCTANT; // 这里和 Fortran 一样只是定义了不用也没关系
const int ex1 = ex[0], ex2 = ex[1], ex3 = ex[2];
// 对应 Fortran: dX = X(2)-X(1) Fortran 1-based
// C: X[1]-X[0]
const double dX = X[1] - X[0];
const double dY = Y[1] - Y[0];
const double dZ = Z[1] - Z[0];
const double d12dx = ONE / F12 / dX;
const double d12dy = ONE / F12 / dY;
const double d12dz = ONE / F12 / dZ;
// Fortran 里算了 d2dx/d2dy/d2dz 但本 subroutine 里没用到(保持一致也算出来)
const double d2dx = ONE / TWO / dX;
const double d2dy = ONE / TWO / dY;
const double d2dz = ONE / TWO / dZ;
(void)d2dx; (void)d2dy; (void)d2dz;
// Fortran:
// imax = ex(1); jmax = ex(2); kmax = ex(3)
const int imaxF = ex1;
const int jmaxF = ex2;
const int kmaxF = ex3;
// Fortran:
// imin=jmin=kmin=1; 若满足对称条件则设为 -2
int iminF = 1, jminF = 1, kminF = 1;
if (Symmetry > NO_SYMM && fabs(Z[0]) < dZ) kminF = -2;
if (Symmetry > EQ_SYMM && fabs(X[0]) < dX) iminF = -2;
if (Symmetry > EQ_SYMM && fabs(Y[0]) < dY) jminF = -2;
// 分配 fh大小 (ex1+3)*(ex2+3)*(ex3+3)
const size_t nx = (size_t)ex1 + 3;
const size_t ny = (size_t)ex2 + 3;
const size_t nz = (size_t)ex3 + 3;
const size_t fh_size = nx * ny * nz;
double *fh = (double*)malloc(fh_size * sizeof(double));
if (!fh) return; // 内存不足:直接返回(你也可以改成 abort/报错)
// Fortran: call symmetry_bd(3,ex,f,fh,SoA)
symmetry_bd(3, ex, f, fh, SoA);
/*
* Fortran 主循环:
* do k=1,ex(3)-1
* do j=1,ex(2)-1
* do i=1,ex(1)-1
*
* 转成 C 0-based
* k0 = 0..ex3-2, j0 = 0..ex2-2, i0 = 0..ex1-2
*
* 并且 Fortran 里的 i/j/k 在 fh 访问时,仍然是 Fortran 索引值:
* iF=i0+1, jF=j0+1, kF=k0+1
*/
for (int k0 = 0; k0 <= ex3 - 2; ++k0) {
const int kF = k0 + 1;
for (int j0 = 0; j0 <= ex2 - 2; ++j0) {
const int jF = j0 + 1;
for (int i0 = 0; i0 <= ex1 - 2; ++i0) {
const int iF = i0 + 1;
const size_t p = idx_ex(i0, j0, k0, ex);
// ---------------- x direction ----------------
const double sfx = Sfx[p];
if (sfx > ZEO) {
// Fortran: if(i+3 <= imax)
// iF+3 <= ex1 <=> i0+4 <= ex1 <=> i0 <= ex1-4
if (i0 <= ex1 - 4) {
f_rhs[p] += sfx * d12dx *
(-F3 * fh[idx_fh_F(iF - 1, jF, kF, ex)]
-F10 * fh[idx_fh_F(iF , jF, kF, ex)]
+F18 * fh[idx_fh_F(iF + 1, jF, kF, ex)]
-F6 * fh[idx_fh_F(iF + 2, jF, kF, ex)]
+ fh[idx_fh_F(iF + 3, jF, kF, ex)]);
}
// elseif(i+2 <= imax) <=> i0 <= ex1-3
else if (i0 <= ex1 - 3) {
f_rhs[p] += sfx * d12dx *
( fh[idx_fh_F(iF - 2, jF, kF, ex)]
-EIT * fh[idx_fh_F(iF - 1, jF, kF, ex)]
+EIT * fh[idx_fh_F(iF + 1, jF, kF, ex)]
- fh[idx_fh_F(iF + 2, jF, kF, ex)]);
}
// elseif(i+1 <= imax) <=> i0 <= ex1-2循环里总成立
else if (i0 <= ex1 - 2) {
f_rhs[p] -= sfx * d12dx *
(-F3 * fh[idx_fh_F(iF + 1, jF, kF, ex)]
-F10 * fh[idx_fh_F(iF , jF, kF, ex)]
+F18 * fh[idx_fh_F(iF - 1, jF, kF, ex)]
-F6 * fh[idx_fh_F(iF - 2, jF, kF, ex)]
+ fh[idx_fh_F(iF - 3, jF, kF, ex)]);
}
} else if (sfx < ZEO) {
// Fortran: if(i-3 >= imin)
// (iF-3) >= iminF <=> (i0-2) >= iminF
if ((i0 - 2) >= iminF) {
f_rhs[p] -= sfx * d12dx *
(-F3 * fh[idx_fh_F(iF + 1, jF, kF, ex)]
-F10 * fh[idx_fh_F(iF , jF, kF, ex)]
+F18 * fh[idx_fh_F(iF - 1, jF, kF, ex)]
-F6 * fh[idx_fh_F(iF - 2, jF, kF, ex)]
+ fh[idx_fh_F(iF - 3, jF, kF, ex)]);
}
// elseif(i-2 >= imin) <=> (i0-1) >= iminF
else if ((i0 - 1) >= iminF) {
f_rhs[p] += sfx * d12dx *
( fh[idx_fh_F(iF - 2, jF, kF, ex)]
-EIT * fh[idx_fh_F(iF - 1, jF, kF, ex)]
+EIT * fh[idx_fh_F(iF + 1, jF, kF, ex)]
- fh[idx_fh_F(iF + 2, jF, kF, ex)]);
}
// elseif(i-1 >= imin) <=> i0 >= iminF
else if (i0 >= iminF) {
f_rhs[p] += sfx * d12dx *
(-F3 * fh[idx_fh_F(iF - 1, jF, kF, ex)]
-F10 * fh[idx_fh_F(iF , jF, kF, ex)]
+F18 * fh[idx_fh_F(iF + 1, jF, kF, ex)]
-F6 * fh[idx_fh_F(iF + 2, jF, kF, ex)]
+ fh[idx_fh_F(iF + 3, jF, kF, ex)]);
}
}
// ---------------- y direction ----------------
const double sfy = Sfy[p];
if (sfy > ZEO) {
// jF+3 <= ex2 <=> j0+4 <= ex2 <=> j0 <= ex2-4
if (j0 <= ex2 - 4) {
f_rhs[p] += sfy * d12dy *
(-F3 * fh[idx_fh_F(iF, jF - 1, kF, ex)]
-F10 * fh[idx_fh_F(iF, jF , kF, ex)]
+F18 * fh[idx_fh_F(iF, jF + 1, kF, ex)]
-F6 * fh[idx_fh_F(iF, jF + 2, kF, ex)]
+ fh[idx_fh_F(iF, jF + 3, kF, ex)]);
} else if (j0 <= ex2 - 3) {
f_rhs[p] += sfy * d12dy *
( fh[idx_fh_F(iF, jF - 2, kF, ex)]
-EIT * fh[idx_fh_F(iF, jF - 1, kF, ex)]
+EIT * fh[idx_fh_F(iF, jF + 1, kF, ex)]
- fh[idx_fh_F(iF, jF + 2, kF, ex)]);
} else if (j0 <= ex2 - 2) {
f_rhs[p] -= sfy * d12dy *
(-F3 * fh[idx_fh_F(iF, jF + 1, kF, ex)]
-F10 * fh[idx_fh_F(iF, jF , kF, ex)]
+F18 * fh[idx_fh_F(iF, jF - 1, kF, ex)]
-F6 * fh[idx_fh_F(iF, jF - 2, kF, ex)]
+ fh[idx_fh_F(iF, jF - 3, kF, ex)]);
}
} else if (sfy < ZEO) {
if ((j0 - 2) >= jminF) {
f_rhs[p] -= sfy * d12dy *
(-F3 * fh[idx_fh_F(iF, jF + 1, kF, ex)]
-F10 * fh[idx_fh_F(iF, jF , kF, ex)]
+F18 * fh[idx_fh_F(iF, jF - 1, kF, ex)]
-F6 * fh[idx_fh_F(iF, jF - 2, kF, ex)]
+ fh[idx_fh_F(iF, jF - 3, kF, ex)]);
} else if ((j0 - 1) >= jminF) {
f_rhs[p] += sfy * d12dy *
( fh[idx_fh_F(iF, jF - 2, kF, ex)]
-EIT * fh[idx_fh_F(iF, jF - 1, kF, ex)]
+EIT * fh[idx_fh_F(iF, jF + 1, kF, ex)]
- fh[idx_fh_F(iF, jF + 2, kF, ex)]);
} else if (j0 >= jminF) {
f_rhs[p] += sfy * d12dy *
(-F3 * fh[idx_fh_F(iF, jF - 1, kF, ex)]
-F10 * fh[idx_fh_F(iF, jF , kF, ex)]
+F18 * fh[idx_fh_F(iF, jF + 1, kF, ex)]
-F6 * fh[idx_fh_F(iF, jF + 2, kF, ex)]
+ fh[idx_fh_F(iF, jF + 3, kF, ex)]);
}
}
// ---------------- z direction ----------------
const double sfz = Sfz[p];
if (sfz > ZEO) {
if (k0 <= ex3 - 4) {
f_rhs[p] += sfz * d12dz *
(-F3 * fh[idx_fh_F(iF, jF, kF - 1, ex)]
-F10 * fh[idx_fh_F(iF, jF, kF , ex)]
+F18 * fh[idx_fh_F(iF, jF, kF + 1, ex)]
-F6 * fh[idx_fh_F(iF, jF, kF + 2, ex)]
+ fh[idx_fh_F(iF, jF, kF + 3, ex)]);
} else if (k0 <= ex3 - 3) {
f_rhs[p] += sfz * d12dz *
( fh[idx_fh_F(iF, jF, kF - 2, ex)]
-EIT * fh[idx_fh_F(iF, jF, kF - 1, ex)]
+EIT * fh[idx_fh_F(iF, jF, kF + 1, ex)]
- fh[idx_fh_F(iF, jF, kF + 2, ex)]);
} else if (k0 <= ex3 - 2) {
f_rhs[p] -= sfz * d12dz *
(-F3 * fh[idx_fh_F(iF, jF, kF + 1, ex)]
-F10 * fh[idx_fh_F(iF, jF, kF , ex)]
+F18 * fh[idx_fh_F(iF, jF, kF - 1, ex)]
-F6 * fh[idx_fh_F(iF, jF, kF - 2, ex)]
+ fh[idx_fh_F(iF, jF, kF - 3, ex)]);
}
} else if (sfz < ZEO) {
if ((k0 - 2) >= kminF) {
f_rhs[p] -= sfz * d12dz *
(-F3 * fh[idx_fh_F(iF, jF, kF + 1, ex)]
-F10 * fh[idx_fh_F(iF, jF, kF , ex)]
+F18 * fh[idx_fh_F(iF, jF, kF - 1, ex)]
-F6 * fh[idx_fh_F(iF, jF, kF - 2, ex)]
+ fh[idx_fh_F(iF, jF, kF - 3, ex)]);
} else if ((k0 - 1) >= kminF) {
f_rhs[p] += sfz * d12dz *
( fh[idx_fh_F(iF, jF, kF - 2, ex)]
-EIT * fh[idx_fh_F(iF, jF, kF - 1, ex)]
+EIT * fh[idx_fh_F(iF, jF, kF + 1, ex)]
- fh[idx_fh_F(iF, jF, kF + 2, ex)]);
} else if (k0 >= kminF) {
f_rhs[p] += sfz * d12dz *
(-F3 * fh[idx_fh_F(iF, jF, kF - 1, ex)]
-F10 * fh[idx_fh_F(iF, jF, kF , ex)]
+F18 * fh[idx_fh_F(iF, jF, kF + 1, ex)]
-F6 * fh[idx_fh_F(iF, jF, kF + 2, ex)]
+ fh[idx_fh_F(iF, jF, kF + 3, ex)]);
}
}
}
}
}
free(fh);
}